(x-5)^2+32=4

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Solution for (x-5)^2+32=4 equation: 



(x-5)^2+32=4

We move all terms to the left:

(x-5)^2+32-(4)=0

We add all the numbers together, and all the variables

(x-5)^2+28=0

We move all terms containing x to the left, all other terms to the right

(x-5)^2=-28

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